In this case the population standard deviation is unknown. We only have the sample standard deviation s. Then,
the confidence interval formula for estimating the population mean is
![\bar{x}-T_c\frac{s}{\sqrt[]{n}}<\mu<\bar{x}+Tc\frac{s}{\sqrt[]{n}}](https://img.qammunity.org/2023/formulas/mathematics/college/x13854b4u3pxa0g2mvn8v3h2uhmtjkfdjb.png)
where Tc is the critical T-value, which depends on the confidence level. For the 95% confidence level and n=26, the T value is

Then, by substituting this value and the given ones into the confidence interval, we have
![37-(2.060)\frac{11}{\sqrt[]{26}}<\mu<37+(2.060)\frac{11}{\sqrt[]{26}}](https://img.qammunity.org/2023/formulas/mathematics/college/w8x21ptoxn33uti5czl9bco108j7u5npq0.png)
which gives

By rounding to 3 decimal places, the answer is
