Total spendable budget = $28
Admission Fee = $6.50
Amount left after admission fee is paid = 28 - 6.50 = $21.5
She is to spend $21.5 on food and rides.
Each ride costs $3.
However, we seek the maximum number of rides Jan can make. We seek the highest multiple of 3 less than 21.5. That leaves us with $21
This gives max number of rides to be:
![(21)/(3)=7](https://img.qammunity.org/2023/formulas/mathematics/middle-school/3w1gddhfz60lv801z2wno89e9h7tlt4jn8.png)
7 is the maximum number of rides she can make at $3 per ride while she spends the remaining $0.5 on food since we know that the $21.5 was spent on rides and food.