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Using the side lengths, determine what type of triangle would be created, if any.2,4,53,4,56.7.87.9.153, 3, 10** AcuteRight* Obtuse:: Cannot form a triangle

Using the side lengths, determine what type of triangle would be created, if any.2,4,53,4,56.7.87.9.153, 3, 10** AcuteRight-example-1
User Jbcedge
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1 Answer

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Let a, b,c be the sides of a triangle and c be the larger side.

A triangle can be formed by the sides a,b and c only if,


\begin{gathered} a+b>c \\ b+c>a \\ c+a>b \end{gathered}

Then, if


\begin{gathered} c^2=a^2+b^2 \\ \end{gathered}

The triangle is right angled.

If,


c^2>a^2+b^2

The triangle is obtuse.

If,


c^2The triangle is acute.<p></p><p>Consider sides 2, 4,5.</p><p>The sum of any two sides is greater than the third side. So, a triangle can be formed by the sides 2,4, and 5. 5 is the length of the largest side. </p>[tex]\begin{gathered} 5^2>2^2+4^2 \\ 25>4+16 \end{gathered}

Hence, 2,4,5 are the sides of an obtuse angled triangle.

Consider sides 3, 4, 5.

The sum of any two sides is greater than the third side. So, a triangle can be formed by the sides 3, 4, and 5. 5 is the length of the largest side.


\begin{gathered} 5^2=3^2+4^2 \\ 25=9+16 \end{gathered}

Hence, 3,4 and 5 are the sides of a right angled triangle.

Consider sides 6,7,8.

The sum of any two sides is greater than the third side. So, a triangle can be formed by the sides 6, 7, and 8. 8 is the length of the largest side.


\begin{gathered} 8^2<6^2+7^2 \\ 64<36+49 \end{gathered}

Hence, 6,7 and 8 are the sides of an acute angled triangle.

Consider sides 7,9,15.

The sum of any two sides is greater than the third side. So, a triangle can be formed by the sides 7, 9, and 15. 15 is the length of the largest side.


15^2>7^2+9^2

Hence, 7, 9and 15 are the sides of an obtuse angled triangle.

Consider sides 3,3,10.

The sum of any two sides is not greater than the third side. So, a triangle cannot be formed by the sides 3,3 and 10.

User Bizmate
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