Question

A. Translate the verbal phrases into algebraic expressions.1. 13 times b plus 22. 27 multiplied to w divided by 33. The square of the quotient of 54 and j4. K divided by the square root of 65. Q to the 10th power subtracted from 100

Answer 1

Step-by-step explanation

So first of all we have "13 times b plus 2". 13 times b is given by just taking the variable and multiplying it by 13:

`13\cdot b=13b`

Then we add 2 to this expression so we get:

`13b+2`

At item 2 we have "27 multiplied to w divided by 3". We first multiply 27 and w:

`27\cdot w=27w`

Then we divide this expression by 3:

`(27w)/(3)`

In item 3 we have "The square of the quotient of 54 and j". We first write the quotient of 54 and j:

`((54)/(j))`

Then we square it:

`((54)/(j))^2`

At 4. we have "K divided by the square root of 6". The square root of 6 is:

`√(6)`

Then we take K and we divide it by this root:

`(K)/(√(6))`

Finally, we must translate "Q to the 10th power subtracted from 100​". Q to the 10th power is:

`Q^(10)`

Then we take 100 and we substract the last expression:

`100-Q^(10)`Answer

Then the answers are:

`\begin{gathered} 1.\text{ }13b+2 \\ 2.\text{ }(27w)/(3) \\ 3.\text{ }((54)/(j))^2 \\ 4.\text{ }(K)/(√(6)) \\ 5.\text{ }100-Q^(10) \end{gathered}`