Question

Use the quadratic formula to solve for the zero(s) of the equation y = -0.125x2 + 0.35x + 0.75. Round to the nearest hundredth.

Answer 1

Given:

There is a expression given as

`-0.125x^2+0.35x+0.75=y`

Required:

We need to find the Zeros of given expression

Step-by-step explanation:

`\begin{gathered} -0.125x^2+0.35x+0.75=0 \\ -125x^2+350x+750=0 \end{gathered}`

now compare the given equation with

`ax^2+bx+c=0`

a=-125

b=350

c=750

now by using the quadratic formula

`x_1,x_2=(-b\pm√(b^2-4ac))/(2a)=(-350\pm√(350^2-4\left(-125\right)\cdot\:750))/(2\left(-125\right))`

after simplify