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Show why m1is the same as mHint: Start at (0, 0)-1-2

Show why m1is the same as mHint: Start at (0, 0)-1-2-example-1

1 Answer

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Given :

m=1/2 and the point on the line is (0,0).

The equation of the line is


y=mx+b

where m is slope and b is y itercept.

The y-intercept is the point where the lie crosses the y-axis.

(0,0) is the y-intercepet point.

we get b=0.

Substitute m=1/2 and b=0 in the line equation, we get


y=(1)/(2)x+0

The line equation is


y=(1)/(2)x

Similarly, replacing m=-1/-2 and b=0 in the line equation, we get


y=(-1)/(-2)x

Set x=0, we get


y=(-1)/(-2)(0)

We get the point (0,0).

Set x=2, we get


y=(-1)/(-2)(2)
y=1

We get the point (2,1).

Set x=-2, we get


y=(-1)/(-2)(-2)


y=-1

We get the point (-2,-1).

Mark th epoints (0,0), (2,1) and (-2,-1).

Join all the points by ray.

we get the same line.

Hence we get that


m=(1)/(2)=(-1)/(-2)

Show why m1is the same as mHint: Start at (0, 0)-1-2-example-1
User Henrik Olsson
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