217k views
2 votes
72. |x - 3x5| = 6 + y|9-y + 6| =21In the equations above, y<0. Which of the following could be the value of x?E. -15F. -3G. 3H. 15

1 Answer

2 votes

We are given

|x - 3x5| = 6 + y

|9 - y + 6| = 21

We are given a condition that y < 0, and this implies that y can range from -1 to -20

For the first equation

|x - 15 | = 6 + y

This is an absolute function, and it can be written in two forms

(x - 15) = 6 + y or -(x - 15) = 6 + y

(x - 15) = 6 + y

x - 15 = 6 + y

x = 6 + y + 15

x = y + 21

-(x - 15) = 6 + y

Open the parenthesis by multiplying through by -

-x + 15 = 6 + y

-x = 6+ y - 15

-x = (-9 + y)

x = 9 - y

The second absolute function is given as

(9 - y + 6) = 21

-y + 15 = 21

-y = 21 - 15

-y = 6

y = -6

Substitute the value of y into the above equations

For the first value of x

x = y + 21

x = -6 + 21

x = 15

For the second equation

x = 9 - y

x = 9 - (-6)

x = 9 + 6

x = 15

When y = -6, x = 15

The answer is 15

User Sergio Mendez
by
3.4k points