Answer:
Maas of sodium sulphate produced = moles×molar mass=0.06×142=8.52 gmoles\times molar\ mass=0.06\times 142=8.52\ gmoles×molar mass=0.06×142=8.52 g
Step-by-step explanation:
Reaction between them is given by-
2NaOH +H2SO4 → Na2SO4 +2H2O2NaOH\ \ +H_2SO_4\ \to\ Na_2SO_4\ \ +2H_2O2NaOH +H2SO4 → Na2SO4 +2H2O
Molar mass of H2SO4=98 g mole−1H_2SO_4=98\ g\ mole^{-1}H2SO4=98 g mole−1
Moles of sulphuric acid taken = 5.8898=0.06 mole\frac{5.88}{98}=0.06\ mole985.88=0.06 mole
Moles of sodium hydroxide taken = 6.240=0.155 mole\frac{6.2}{40}=0.155\ mole406.2=0.155 mole
here sulphuric acid is limiting agent so
reaction will proceed according to sulphuric acid
0.06 mole HSO4 will produce same amount of Na2SO40.06\ mole\ H_SO_4\ will \ produce\ same\ amount\ of \ \ Na_2SO_4\\0.06 mole HSO4 will produce same amount of Na2SO4