( 1/3m^2n^2)^4 ( 9m^8 n^3)^2
Assuming 1/3 is a fraction and m and n are in the numerator
The power 4 needs to be applied to each term in the parentheses
( 1/3m^2n^2)^4 = 1/3 ^4 * m^2^4 * n^2^4
We know a^b^c = a^(b*c)
1/81 * m^8 n^8
We do the same for ( 9m^8 n^3)^2
9^2 m^8^2 n^3^2 = 81 m^16 n^6
Now multiply these together
1/81 * m^8 n^8 * 81 m^16 n^6
1/81 * 81 m^8 * m^16 n^8 * n^6
We know a^b * a^c = a^(b+c)
1 m^(8+16) n^(8+6)
m^24 n^14
Answer: m^24 n^14