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27 votes
27 votes
A girl of mass 50.0 kg sits on the right-hand side of a seesaw at a distance of 3.4 m

from its pivot. Another girl of weight 450 N sits on the left-hand side. At what distance

from the pivot must she sit to balance the seesaw? Use g = 10.0 m/s2​

User Hans Sjunnesson
by
3.3k points

1 Answer

22 votes
22 votes

Answer:

3.78 m on the left side of the seesaw

Step-by-step explanation:

The net torque in this situation is zero, so the torque from each side of the pivot point must balance each other out:

(50.0 kg x 10.0 m/s^2)(3.4m) = (450 N) r

Solve for r, and you get 3.78 on the left side.

Hope this helps!

User Mateusz Kornecki
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2.8k points