Question

Calculate the mean absolute deviation for peppers from Abridge Farm.

Answer 1

`Mean\text{ Absolute Deviation = 0.49}`

Step-by-step explanation:

Here, we want to calculate the mean absolute deviation

To do this, we start by calculating the value of the mean

This is the sum of the weights divided by the count of the weight which is 10

We have the mean as follows:

`\begin{gathered} (3.2+4.3+3.9+4.3+4.1+3.8+4.9+5.2+4.3+3.1)/(10) \\ =^{}(41.1)/(10)\text{ = 4.11} \end{gathered}`

To get the mean absolute deviation, we subtract the mean from each of the numbers, find the absolute values (turning the neagtives to positives) of these numbers. Sum them together and divide by the count of the numbers which is 10

We have this as follows:

3.2 - 4.11 = -0.91

4.3-4.11 = 0.19

3.9-4.11=-0.21

4.3-4.11=0.19

4.1-4.11=-0.01

3.8-4.11 = -0.31

4.9-4.11 = 0.79

5.2-4.11= 1.09

4.3-4.11 = 0.19

3.1-4.11= 1.01

The next thing to do here is to sum up all the differences after turning the negative values to positive. We then divide this sum result by the count of values which is 10

Mathematically, we have this as:

`\begin{gathered} \frac{0.91\text{ +0.19+0.21+0.19 + 0.01+0.31+0.79+1.09+0.19+1.01}}{10} \\ =\text{ 0.49} \end{gathered}`