206k views
1 vote
What is the intermediate step in the form (x+a)^2=b as a result of completing the square for the following equation? x^2+16x=14x+191

1 Answer

0 votes

The given expression is

x^2 + 16x = 14x + 191

The first step is to subtract 14x from both sides of the expression. Thus, we have

x^2 + 16x - 14x = 14x - 14x + 191

x^2 + 2x = 191

To complete the square, we would add the square of half the coefficient of x to both sides of the equation. The coefficient off x is 2. Half of 2 is 1. Thus, we have

x^2 + 2x + 1^2 = 191 + 1^2

(x + 1)^2 = 191 + 1

(x + 1)^2 = 192

Thus, the intermediate step is (x + 1)^2 = 192

User Laurent Lyaudet
by
3.6k points