Question

How can I solve 4x^2 + 12x > -x -3

Answer 1

He have the following:

`4x^2+12x>-x-3​`

solving:

`\begin{gathered} 4x^2+12x+x+3>-x-3+x+3​ \\ 4x^2+13x+3>0 \\ \text{factoring} \\ (4x+1)(x+3)>0 \\ (4x+1)>0\rightarrow4x+1-1>-1\rightarrow(4x)/(4)>-(1)/(4)\rightarrow x>-(1)/(4) \\ (x+3)<0\rightarrow x+3-3<0-3\rightarrow x<-3 \\ \text{the solution is} \\ (-\infty,-3)U(-(1)/(4),\infty) \end{gathered}`