ANSWER
![602.1Hz](https://img.qammunity.org/2023/formulas/physics/college/a5gy2fd7timcuue3h3b61ks6br1jxvtzsd.png)
Step-by-step explanation
To find the frequency that the motorcyclist hears, we have to apply the rules of the Doppler effect. Doppler effect describes the change in perceived frequency of a wave based on the observer and the source of the wave.
For an object moving toward the source of the wave, we have that the frequency is:
![f^(\prime)=((v+v_0))/((v-v_s))f](https://img.qammunity.org/2023/formulas/physics/college/4iovmu5od6nndpuzrritp4hac7grk8u231.png)
where v = velocity of sound waves
v0 = velocity of motorcyclist
vs = velocity of source of sound
f = frequency
Therefore, substituting the given values, we have that the frequency that the motorcyclist hears is:
![\begin{gathered} f^(\prime)=(343+14.8)/(343-32.2)\cdot523 \\ f^(\prime)=(357.8)/(310.8)\cdot523 \\ f^(\prime)=602.1Hz \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/nd4xdh6z8e912d0iab9e0jv3otr0iuwris.png)
That is the answer.