Question

Suppose a normal distribution has a mean of 79 and astandard deviation of 7.

Answer 1

The probability can be calculated using the z-score:

`z=\frac{x-\bar{x}}{\sigma}`

From the question, the following parameters are given:

`\begin{gathered} x=72 \\ \bar{x}=79 \\ \sigma=7 \end{gathered}`

The z-score is calculated as follows:

`\begin{gathered} z=(72-79)/(7)=-(7)/(7) \\ z=-1 \end{gathered}`

The probability is calculated using tables. Therefore:

`P(z\geq-1)=0.8413`

The correct option is OPTION C.