Question

1. Re-arrange the Ohm’s Law equation to solve the following:I = Type your answers here.R = Type your answers here.2. Power is equal to voltage multiplied by current. Add the missing information in each of the following power equations.P = V Type your answers here.P = R Type your answers here.P = V2 Type your answers here.

Answer 1

`\begin{gathered} 1)I=(V)/(R) \\ R=(V)/(I) \end{gathered}`

2)

`\begin{gathered} P=VI \\ P=RI^2 \\ P=(V^2)/(R) \end{gathered}`

Step-by-step explanation

Step 1

Ohm's law states that the strength of a direct current is directly proportional to the potential difference and inversely proportional to the resistance of the circuit.

`I=(V)/(R)`

so

a)

`I=(V)/(R)`

b)

`\begin{gathered} I=(V)/(R) \\ \text{Multiply both sides by R} \\ I\cdot R=R\cdot(V)/(R) \\ IR=V \\ \text{divide both sides by I} \\ (RI)/(I)=(V)/(I) \\ R=(V)/(I) \end{gathered}`

Step 2

2

let

Power is equal to voltage multiplied by current.

so

`P=VI\rightarrow(1)`

also, replacing

`\begin{gathered} P=VI \\ P=(IR)I \\ P=RI^2\rightarrow(2) \\ \end{gathered}`

also

`\begin{gathered} V^2=I^2R^2 \\ \text{hece} \\ I^2=(V^2)/(R^2) \\ \\ \text{therefore, } \\ P=RI^2\rightarrow(2) \\ P=(V^2)/(R^2)\cdot R \\ P=(V^2)/(R) \end{gathered}`

I hope this helps you