Question

A record player rotates clockwise at 45 rpm (revolutions per minute) find the period

Answer 1

1.33 seconds

Step-by-step explanation:

First, we need to convert 45 revolutions per minute into hertz or revolutions per second. So:

`45\text{ rev/min }*\frac{1\text{ min}}{60\text{ s}}=0.75\text{ rev/sec}`

It means that 0.75 rev/sec or 0.75 Hz is the frequency. Then, the period will be equal to the inverse of the frequency, so the period is equal to:

`T=(1)/(f)=\frac{1}{0.75\text{ rev/sec}}=1.33\text{ seconds}`

Therefore, the answer is 1.33 seconds