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How does this work? I’ve been trying to figure it out but have not been able to.

How does this work? I’ve been trying to figure it out but have not been able to.-example-1
User Aranxo
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1 Answer

3 votes

We have to graph a linen with slope 2 and that contains the point (-3,-1).

We can use this information to write the equation of the line in slope-point form:


\begin{gathered} y-y_0=m(x-x_0) \\ y-(-1)=2(x-(-3)) \\ y+1=2(x+3) \\ y=2x+2\cdot3-1 \\ y=2x+6-1 \\ y=2x+5 \end{gathered}

We can graph the line without knowing the equation, only knowing a single point of the line and the slope:

- We plot the point (x0,y0).

- We calculate a second point where we add one unit to x-coordinate from x0 and m units to the y-coordinate: (x0+1, y0+m).

NOTE: This is because, if we have an slope m, this means that y increases m units for each unit increase in x. We can write it for any point generally as (x0+k, y0+k*m).

Then, we plot the point (-3,-1).

The second point of thte line to plot it will be:


(x_0+1,y_0+m)=(-3+1,-1+2)=(-2,1)

Then, with two points of the line we draw the line that pass through those points (-3,-1) and (-2,1):

How does this work? I’ve been trying to figure it out but have not been able to.-example-1
User Jsherk
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