Answer;

Explanation;
To solve this, we are going to use one of the logarithm rules
The rule is the subtraction and/or the division rule and it applies to logarithms having the same base
It can be summarized as;

Looking at the question, we can see that we have an exponent; hence we shall be needing the exponent rule for logarithms here too. It can be represented as follows;

So, we shall be applying these two rules to solve the problem at hand
