Question

What is the measure of one interior angle of a regular 40-gon

Answer 1

The sum of intern angles of any polygon is represented by the following expression:

`\begin{gathered} (n-2)\cdot180 \\ \text{whre,} \\ n\text{ is the number of vertices} \end{gathered}`

Since a 40-gon, has 40 vertices, the sum of its intern angles would be:

`\begin{gathered} (40-2)\cdot180=6840\text{ degrees} \\ \end{gathered}`

Then, each angle have a measure:

`(6840)/(40)=171\text{ degrees}`