Given:
It is given that the length of a shadow of a building is 56 ft when the sun is 70° above the horizon.
Find:
we have to find the height of the building.
Step-by-step explanation:
we know in trigonometry that

here angle is 70 degree, base is 56 ft.
Let h be the perpendicular, i.e. height of the building
Therefore, we get

Therefore, the height of the building is 153.8 ft (by rounded to nearest tenth)