Question

The perimeter of a triangle is 93 ft. Side A of thetriangle is twice as long as side B. Side c is 3 ftlonger than side A. Find the length of each side.

Answer 1

The perimeter P of a triangle is;

`\text{Side A + Side B + Side C}`

Let side A be a. side B be b and side C be c;

`\begin{gathered} a=2b \\ c=3+a=3+2b \end{gathered}`
`\text{Perimeter P= 93ft}`
`\begin{gathered} P=a+b+c \\ 93=2b+b+3+2b \\ 93-3=5b \\ 5b=90 \\ b=(90)/(5) \\ b=18ft \end{gathered}`

Then,

`\begin{gathered} a=2b \\ a=2(18)_{} \\ a=36ft \end{gathered}`

So,

`\begin{gathered} c=3+a \\ c=3+36 \\ c=39ft \end{gathered}`

The length of each of the sides is;

`\begin{gathered} a=36ft \\ b=18ft \\ c=39ft \end{gathered}`