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Solve for the measure of each angle. Trigonometry.

Solve for the measure of each angle. Trigonometry.-example-1
User Zeitounator
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1 Answer

12 votes
12 votes

Answer:

∠A=26º

∠B=137º

∠C=17º

Explanation:

We can use the Law of Cosines because we have all 3 side lengths.

cosA =
b^2+c^2-a^2/2bc

cosA=28^2+12^2-18^2 / 2(28)(12)

cosA=604/672

cos-1(604/672

angle A ≈ 26º

cosB =
c^2+a^2-b^2/2ca

cosB=-316/432

cos-1(-316/432

angle B ≈ 137º

26+137=163

180-163=17

angle C ≈ 17º

User Mohammad Shahnawaz
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