Question

You are ordering a hamburger and can get up to 6 toppings, but each topping can only be used once. You tell the cashier to surprise you with the toppings you get.What is the probability that you get 3 toppings? Express your answer as a fraction or a decimal number rounded to four decimal places.

Answer 1

1/120

Explanation:

The number of possible toppings = 6

Each topping can only be used once.

We want to find the probability that you get 3 toppings.

`\begin{gathered} \text{P\lparen1st topping\rparen}=(1)/(6) \\ \text{P\lparen2nd topping\rparen}=(1)/(5) \\ \text{ P\lparen3rd topping\rparen}=(1)/(4) \end{gathered}`

Therefore, the probability that you get 3 toppings is:

`\begin{gathered} \text{ P\lparen3 toppings\rparen}=(1)/(6)*(1)/(5)*(1)/(4) \\ =(1)/(120) \end{gathered}`

The probability that you get 3 toppings is 1/120.