Question

Find the area the sector.arc circle 8A. 147π4 mi²B. 196π3 mi²C. 15π2 mi²D. 119π6 mi²All the multiple choices are in fraction!

Answer 1

As we can see in the image the segment that was removed is 90°, which implies 174 of the circle, therefore the area should be 3/4 of the total area. So:

`A_T=\pi r^2`

So:

`\begin{gathered} A_T=\pi*(7mi)^2 \\ A_T=49\pi\text{ }mi^2 \end{gathered}`

Now, the sector area has to be:

`A_S=(3)/(4)A_T=(3)/(4)49\pi=(147\pi)/(4)mi^2`

The answer is A. 147pi/4 mi^2.