1 Answer

CJCombrink · Answer 1 · 2023-09-03T06:41:01+0000

In the figure above, ABCD is a trapezoid with EF as its midsegment;

Length of |AB| = 18

Length of |CD| = 26

The midsegment of the trapezoid is given as;

$\begin{gathered} |EF|=(1)/(2)(|AB|+|CD|) \\ \end{gathered}$
undefined

Please log in or register to add a comment.