Question

An object travels 50 m in 4 s. It had no initial velocity and experiences constant acceleration. What is the magnitude of the acceleration? x = xo + vo t + ½ a t 2 g = 9.8 m/s2 (downward)

Answer 1

`\begin{gathered} x=50m \\ t=\text{ 4 s} \\ v_o=0m/s,x_o=0m \\ a=\text{?} \\ x=x_o+v_ot+\text{ }(at^2)/(2) \\ x=(at^2)/(2) \\ x=\text{ }(at^2)/(2) \\ \text{solving a} \\ 2x_{}=at^2 \\ a=(2x)/(t^2) \\ a=(2(50m))/((4s)^2)=(100m)/(16s^2)=6.25m/s^2 \\ \text{the }magnitude\text{ of the acceleration is }6.25m/s^2 \end{gathered}`