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The probabilities that a randomly selected house has garage space for 0, 1, 2, or 3 cars are 0.22, 0.33, 0.37, and 0.08, respectively. Display this information as a probability distribution by filling in the blanks.XP(X)

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In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data:

garage space probabiity data

Step 02:

p(0) = 0.22

p (1) = 0.33

p(2) = 0.37

p(3) = 0.08

x 0 1 2 3

p(x) 0.22 0.33 0.37 0.08

That is the full solution.

User Meso
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