Question

James walked for 45 minutes at a rate of 4 mph and then run for 30 minutes at a rate of 10 mph.How many miles have James gone combined?

Answer 1

Given data:

* The time for which James walked with u = 4 mph is,

`\begin{gathered} t_1=45\text{ minutes} \\ t_1=45*60\text{ seconds} \\ t_1=2700\text{ seconds} \end{gathered}`

* The time for which James run with speed v = 10 mph is,

`\begin{gathered} t_2=30\text{ minutes} \\ t_2=30*60\text{ seconds} \\ t_2=1800\text{ seconds} \end{gathered}`

Solution:

The distance traveled in the first 2700 seconds is,

`d_1=ut_1`

Substituting the known values,

`\begin{gathered} d_1=4*2700 \\ d_1=10800\text{ miles} \end{gathered}`

The distance traveled by James in the next 1800 seconds is,

`\begin{gathered} d_2=vt_2 \\ d_2=10*1800 \\ d_2=18000\text{ miles} \end{gathered}`

Thus, the total distance traveled by James is,

`\begin{gathered} D=d_1+d_2 \\ D=10800+18000 \\ D=28800\text{ miles} \end{gathered}`

Thus, the total distance traveled is 28800 miles.