Question

Solve the equation 2x2 + 11x – 3 = 0 to the nearest tenth.

Answer 1

`\begin{gathered} 2x^2+11x-3=0\rightarrow \\ x=\frac{-11+\sqrt[]{121-4\cdot2\cdot-3}}{4}=\frac{-11+\sqrt[]{145}}{4}\approx0.26 \\ x=\frac{-11-\sqrt[]{121-4\cdot2\cdot-3}}{4}=\frac{-11-\sqrt[]{145}}{4}\approx-5.76 \end{gathered}`