Question

The mass of an object is Adding of heat will raise the temperature of the object by What is the specific heat of the object?5.60 J/kg ∙ K1400 J/kg ∙ K0.00180 J/kg ∙ K3,500,000 J/kg ∙ K

Answer 1

m = mass = 250g = 0.25 kg

ΔQ = 14 J

ΔT = 10°C

k= specific heat

Use the formula:

ΔQ= kmΔT

Isolate k

k= ΔQ / mΔT

Replacing with the values given:

k = 14 J / ( 0.25 kg* 10°c ) = 5.6 j/kgK