W0e are asked to determine the frequency of a sound given its velocity and wavelength. To do that we will use the following formula:
![v=\lambda f](https://img.qammunity.org/2023/formulas/physics/college/i838uwfyqotnoyo83z5m5nh9ah7vk1pyb2.png)
Where:
![\begin{gathered} v=\text{ velocity} \\ \lambda=\text{ wavelength} \\ f=\text{ frequency} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/8wm70j2pm23ea3m60ppamc117q0yrurk2j.png)
Now, we solve for the frequency by dividing both sides by the wavelength.
![(v)/(\lambda)=f](https://img.qammunity.org/2023/formulas/physics/college/2k097fztr20shna68honyjaefjku2g6ue9.png)
Now, we substitute the values:
![(600(m)/(s))/(15m)=f](https://img.qammunity.org/2023/formulas/physics/college/g4o429c95ji4tmj7n6eqexokk4pbqf2q3r.png)
Solving the operations:
![40Hz=f](https://img.qammunity.org/2023/formulas/physics/college/wj52qb4p4babzywemuzdp0zps83lt820jv.png)
Therefore, the frequency is 40 Hz.