1 Answer

Kitanga Nday · Answer 1 · 2023-10-08T01:38:33+0000

Given:

The area of square 1 is 25 square units.

Its length of the side is,

$\begin{gathered} A=s^2 \\ 25=s^2 \\ s=\pm5 \\ s=5\text{ ( since length can not be negative)} \end{gathered}$

The area of square 2 is 16 square units.

Its length of the side is,

$\begin{gathered} A=s^2 \\ 16=s^2 \\ s=\pm4 \\ s=4\text{ ( since length can not be negative)} \end{gathered}$

It gives,

Consider the right triangle,

$\begin{gathered} 5^2=4^2+x^2 \\ 25-16=x^2 \\ x^2=9 \\ x=\pm3 \\ x=3\text{ ( since length can not be negative)} \end{gathered}$

So, the length of square 3 is 3 units. Its perimeter is given as,

$\begin{gathered} P=4x \\ P=4*3 \\ P=12\text{ units} \end{gathered}$

Answer: the perimeter of square 3 is 12 units.

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