Question

Help with problem 21- there is more to this problem.

Answer 1

EXPLANATION

Let's see the facts:

Velocity of flow = unknown

Rate of flow = 0.75 cfs

Cross-sectional area of the pipe= 8 inches

We need to convert the 8 inches to feet units:

12 inches --> 1 feet

8 inches ---> 8/12 = 2/3 = 0.67 feet

Applying the given equation:

`Velocity_{\text{ }}offlow_(fps)\text{=}\frac{Rate\text{ of flow}}{\text{Cross}-\text{sectional area}}=\frac{0.75\text{cfs}}{2/3\text{ f}eet}=(9)/(8)=1.125\text{ fps}`

Hence, the solution is Velocity of flow= 1.125 fps