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Write a quadratic function that has x intercepts of 12 and 8 and passes through (9,5) what does y=

1 Answer

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1) A quadratic function has the following standard formula

y=ax²+bx +c

X intercepts are the roots, x_1= 12 and x_2=8

2) We can write any quadratic function having the roots and the coefficient of a

This way

y=a(x-x_1)(x- x_2) Plug into that the roots

y=a(x-12)(x-8) And the x and the y-coordinate of that point (9,5)

5=a(9-12)(9-8)

5=a(-3)(-1)

3a=5

a=5/3

3) Now we can write the function

y=5/3(x-12)(x-8)

y=5/3(x²-8x-12x+96)

y=5/3x² -100/3x +160

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