Question

Write an equation of a line that would be perpendicular to y =-x-8

Answer 1

Let:

`y=-x-8`

From that equation:

`m1=-1`

If two lines are perpendicular, then:

`\begin{gathered} m1* m2=-1 \\ m2=1 \end{gathered}`

Given an arbitraty point:

`(x1,y1)=(1,2)`

Using the point slope equation:

`\begin{gathered} y-y1=m(x-x1) \\ y-2=1(x-1) \\ y-2=x-1 \\ y=x+1 \end{gathered}`