Step 1
Molarity = moles of solute/volume of the solution (L)
Molarity units are mol/L or M
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Step 2
Information provided:
Solute = lithium sulfate = Li2SO4 (the molar mass = 110 g/mol approx.)
Mass of Li2SO4 = 734 g
Volume of solution = 2500 mL = 2.500 L
(1 L = 1000 mL)
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Step 3
Moles Li2SO4 = mass Li2SO4/molar mass Li2SO4 = 734 g/110 g/mol = 6.67 moles Li2SO4
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Step 4
Molarity = 6.67 moles/2.500 L = 2.67 mol/L or 2.67 M
Answer: Molarity = 2.67 mol/L