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How do I find the surface area of a cylinder rounded to the nearest 10th

How do I find the surface area of a cylinder rounded to the nearest 10th-example-1
User Karmel
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In general, the surface area of a cylinder is given by the formula below


\begin{gathered} A=2\pi rh+2r^2\pi \\ r\to\text{ radius} \\ h\to\text{ height} \end{gathered}

Therefore, in our case,


\begin{gathered} r=5,h=11 \\ \Rightarrow A=2\pi\cdot55+2\pi\cdot25 \\ \Rightarrow A=2\pi\cdot80 \\ \Rightarrow A=160\pi \end{gathered}

Rounding to the nearest tenth,


\Rightarrow A\approx502.7

Thus, the surface area is 502.7in^2

User MiniGunnR
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