Given the inequality::
![3|x+1|<6](https://img.qammunity.org/2023/formulas/mathematics/high-school/kpo0oh5l9ongm97talr9lyya5lf11c52ay.png)
Let's solve the inequality for x and graph.
To solve for x, first divide both sides of the inequality by 3:
![\begin{gathered} (3|x+1|)/(3)<(6)/(3) \\ \\ |x+1|<2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/juuo01s304og3954r73x74op1xn4guzatz.png)
Since the left side is an absolute value, we have two possible solutions:
![\begin{gathered} x+1<2 \\ \\ AND \\ -(x+1)<2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/ox6o88psc63wfuxjawygbeks69wtlht78c.png)
Let's solve each inequality for x:
![\begin{gathered} x+1<2 \\ \text{ Subtract 1 from both sides:} \\ x+1-1<2-1 \\ x<1 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/n8rmyivs91rfu5r9fnps7o3afmqlv3u2j1.png)
For the second inequality:
![\begin{gathered} -(x+1)<2 \\ -x-1<2 \\ \text{ Add 1 to both sides:} \\ -x-1+1<2+1 \\ -x<3 \\ Divide\text{ both sides by -1:} \\ (-x)/(-1)<(3)/(-1) \\ \\ x>-3 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/ykkujex6bq6vb8drnoc7t999prcbg10bfz.png)
Hence, we have the solutions:
x < 1 and x > -3
Therefore, the solution is:
-3 < x < 1
The graph of the inequality is shown below:
ANSWER:
-3 < x < 1