P(x) =0.2x³ -0.1x² +1.4
1) Considering that table as y, or P(x) and x, the following values:
(2, 2.6) , (12.6, 4)
Notice that the 1st year or year zero is 1990.
2) Let's now plug into those Polynomials one coordinate pair, and check whether it's true:
P(x) =0.2x³ -0.1x² +1.4
P(2) = 0.2x³ -0.1x² +1.4
P(2) =2.6 True
3) Hence, the answer is P(x) =0.2x³ -0.1x² +1.4