Initially= 14g
9 years= 7gr
11 years ?
Initial grams - 9 years grams = Number of grams used
14 gr - 7gr= 7gr
Then we have to divide 7 grams by 9 years and we will know how many grams are used per year.
![\begin{gathered} (7)/(9)=\text{ 0.778 grams per year} \\ \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/h03y8isxbjvq41ja8vv19u616ksqr7ggz7.png)
Then, in 11 years they will use:
0,778 x 11 years = 8.556 grams
Therefore, to know how much radioactive substance is left we have to subtract the initial grams and the grams used after 11 years. So,
14 grams - 8.556 grams = 5.444 grams left.