Question

Find all critical points for the function. Separate multiple answers with a comma

Answer 1

We have the next function

`f(x)=-10x^2-160x+9`

First we need to obtain the first derivate

`f^(\prime)(x)=-20x-160`

Then we find the value of x when the derivate is 0

`\begin{gathered} -20x-160=0 \\ -20x=160 \\ x=(160)/(-20) \\ x=-8 \end{gathered}`

The critical point of the function is x=-8