Question

At a town fair, for one of the game booths contestants pick a single card from a standard deck, and payouts are based on the cards chosen. Find the probability of your cardf. a club and a 6g, a 2 or an aceh. a club, diamond, or spadei. a diamond faced cardj. a red ace I have never had this type of math before

Answer 1

`(1)/(51)`

Step-by-step explanation:

In a standard deck of cards, there are 52 cards, with 4 different suites (13 cards per suit)

Now, we need to know the number of cards that belong to the club suite and also the number of cards that are 6

So, let us get this

there are 13 club cards and there are 4 6's

Now, remember that the picking is without replacement

The probability of picking a club card is 13/52

Now, after picking this, we want to pick a 6

There are 51 cards left out of which we can pick 4 6's

So the probability is 4/51

The final probability value is the product of this two since we are dealing with an 'and'

We have this as:

`(13)/(52)*(4)/(51)\text{ = }(1)/(51)`