Question

Find the PERIMETER AND the AREA of a right triangle whose sides are 3 inches, 4 inches, and 5 inches . ANS. _________. in , A= 2. _____________. i n squared

Answer 1

Let us sketch out the figure first,

Step 1 : Solve for the perimeter of the right angled triangle.

The perimeter of the triangle is the sum of all the sides of the triangle.

`\begin{gathered} \text{Perimeter}=(3+4+5)\text{ inches} \\ =12\text{inches} \end{gathered}`

Hence, the perimeter of the triangle is 12 inches.

Step 2: Solve for the area of the triangle.

Given,

`\begin{gathered} \text{base}=3\text{inches} \\ \text{height}=4\text{inches} \end{gathered}`

The formula for the area of a triangle is,

`\begin{gathered} \text{Area of the triangle=}(1)/(2)* base* height \\ \text{Area}=(1)/(2)*3\text{inches}*4inches \\ \text{Area}=(1)/(2)*12inches^2=6inches^2 \end{gathered}`

Hence, the area of the triangle is 6 inches².