Question

What is the equation of the following line? Be sure to scroll down first to seeall answer options.(-4, 8)(0,0)10A. y=zxB. y=-*O C. y=-2xO D. y = xE. y = 4xF. y = 2x

Answer 1

slope of line is:

`m=(y_2-y_1)/(x_2-x_1)`

Where,

`\begin{gathered} m=\text{slope} \\ (x_1,y_1)=\text{first point.} \\ (x_2,y_2)=\text{second point.} \end{gathered}`

So, slope of line is:

`\begin{gathered} m=(y_2-y_1)/(x_2-x_1) \\ m=(8-0)/(-4-0) \\ m=-(8)/(4) \\ m=-2 \end{gathered}`

General equation of line.

`y=mx+c`
`\begin{gathered} at\text{ point (0,0)} \\ y=mx+c \\ 0=m(0)+c \\ c=0 \end{gathered}`

Then equation of line is:

`\begin{gathered} y=mx+c \\ y=-2x+0 \\ y=-2x \end{gathered}`