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which equation has a real component of 4. A. x2-8x+16= -21 B. x2-4x+4= -25 C. x2 +8x +16 = -21 D. x2 +4x + 4 = -25

User CitizenRon
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1 Answer

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When we take a look at x² - 8x + 16 = -21

x² - 8x + 16 + 21 = 0

x² - 8x + 37 =0

Using quadratic formula


x\text{ = }\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}

a = 1 b =-8 c = 37

substitute the values into the quadratic formula


x=\frac{8\pm\sqrt[]{64-148}}{2}
x=(8)/(2)\pm\frac{\sqrt[]{84}i}{2}
x=4\pm4.58i

Hence, option A has a real component of 4

User Tastyminerals
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