Question

I need help with some questions i did questions 1-3 already

Answer 1

Given the graph below:

3) Horizontal asymptote

The above graph is an exponential function expressed as

`P(t)=a(b)^t\text{ ---- equation 1}`

To evaluate the horizontal asymptote, we need to evaluate the values of a and b.

Thus,

`\begin{gathered} From\text{ the graph, when t=0, P\lparen t\rparen =5} \\ Thus,\text{ substitute these valuaes into equation 1} \\ 5=a(b)^0 \\ 5=a*1 \\ \Rightarrow a=5 \\ \end{gathered}`

Substitute the value of a into equation 1.

Thus, we have

`P(t)=5(b)^t----\text{ equation 2}`

Also,

`\begin{gathered} when\text{ t=1, P\lparen t\rparen=10} \\ substitute\text{ these values into equation 2} \\ 10=5(b)^1 \\ \Rightarrow10=5b \\ divide\text{ both sides by the coefficient of b, which is 5.} \\ (10)/(5)=(5b)/(5) \\ \Rightarrow b=2 \end{gathered}`

Substitute the value of b into equation 2.

Thus, the exponential function P(t) becomes

`P(t)=5(2)^t----\text{ equation 3}`

To evaluate the horizontal asymptote, we take the limit of the function P(t) as t tends to infinity (either positive or negative).

Thus, we have

`\lim_(t\to-\infty)P(t)=\lim_(t\to-\infty)(5(2)^t)=0`

Hence, the horizontal asymptote of the function is at

`P(t)=0`

4) Domain of the function:

The domain of the P(t) function is the set of input values for which the P(t) function is real and defined.

Thus, the domain of the function is

6) y-intercept.

The y-intercept is evaluated to be the value of P(t) when t equals zero.

Thus, at the y-intercept,

`x=0`

Thus, from the exponential function P(t),

`\begin{gathered} P(t)=5(2)^t \\ at\text{ the y-intercept, x=0} \\ P(t)=5(2)^0=5*1 \\ \Rightarrow P(t)=5 \end{gathered}`

Hence, the y-intercept of the function is 5.

This implies that at the snake population was 5 at the year the Scientists started keeping tracks of the population.

7) Point on the graph when x equals 1.

From the graph, the point (x,y) is

`(1,10)`

This implies that at the end of the first year the snake population is 10.

8) The function is an exponential function expressed as

`P(t)=5\cdot2^t`

9) To fill the table shown below:

we substiyute the respective values of t into the function P(t)