Question

A sailor pulls a boat horizontally alongside a dock for 10.0 m with a rope angled at 40.0°. He uses a force of 100.0 N.How much work does he do on the boat?643 J766 J1.00×10^3 J4.00×10^4 J

Answer 1

In order to determine the amount of work done by the sailor, use the following formula:

W = F·d·cosθ

where

F: force applied = 100.0 N

d: distance = 10.0 m

θ: angle between the direction of the applied force and the direction of motion of the boat = 40.0°

replace the previous values of the parameters into the formula for W:

W = (100.0 N)(10.0 m)cos(40.0°)

W = 766.04J

Hence, the work done by the sailor is 766.04 J