Here we have to use the trigonometric formula for right-angled triangle.
This is the structure described in the question. We have to find x which is the angle between the wire and the ground.
From the trigonometric formula of right angled triangle we know that
![\sin x=\frac{opposite\text{ side}}{\text{hypotenuse}}](https://img.qammunity.org/2023/formulas/mathematics/college/wq20pw7iyjbqsxtbc2nsvzkzjiy67071z9.png)
So
![\sin x=(21)/(35)\Rightarrow\sin x=(3)/(5)\Rightarrow x=\sin ^(-1)((3)/(5))\Rightarrow x=36.8642](https://img.qammunity.org/2023/formulas/mathematics/college/3jnjutschymzrrw6211wlakrknu0xsryud.png)
At the top of the pole the wire will make angle with the pole is
![\cos y=\frac{Adjacent}{\text{Hypotenuse}}\Rightarrow\cos y=(21)/(35)\Rightarrow y=\cos ^(-1)((3)/(5))\Rightarrow y=53.1301](https://img.qammunity.org/2023/formulas/mathematics/college/nyxjudcbdxwr3900g87i0xfb6ipcmehfs1.png)
So the wire makes a 53.1301-degree angles with the top of the pole.