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A man pushes a lawn mower on a level lawn with a force of 199 N. If 38% of the force is directed horizontally, how much work is done by the man in pushing the mower 6.1 m? answer in:____J

User Hafichuk
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1 Answer

3 votes

Given:

The applied force on the lawn mower is,


F=199\text{ N}

38% of the force is directed horizontally.

The displacement of the lawn-mower is


d=6.1\text{ m}

To find:

The work done by the man

Step-by-step explanation:

The horizontal force on the lawn mower is,


\begin{gathered} F_H=F*38\text{ \%} \\ =199*(38)/(100) \\ =75.6\text{ N} \end{gathered}

The work is,


\begin{gathered} W=F_H* d \\ =75.6*6.1 \\ =461.2\text{ J} \end{gathered}

Hence, the work is 461.2 J.

User Amuser
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